map_and_lambda.py

# Let's learn some new Python concepts! You have to generate a list of the first N fibonacci numbers, 0 being the first number. Then, apply 
# the map function and a lambda expression to cube each fibonacci number and print the list.

# Concept

# The map() function applies a function to every member of an iterable and returns the result. It takes two parameters: first, the function 
# that is to be applied and secondly, the iterables. 
# Let's say you are given a list of names, and you have to print a list that contains the length of each name.

# >> print (list(map(len, ['Tina', 'Raj', 'Tom'])))  
# [4, 3, 3]  
# Lambda is a single expression anonymous function often used as an inline function. In simple words, it is a function that has only one 
# line in its body. It proves very handy in functional and GUI programming.

# >> sum = lambda a, b, c: a + b + c
# >> sum(1, 2, 3)
# 6
# Note:

# Lambda functions cannot use the return statement and can only have a single expression. Unlike def, which creates a function and assigns 
# it a name, lambda creates a function and returns the function itself. Lambda can be used inside lists and dictionaries.

# Input Format

# One line of input: an integer N.

# Constraints
# 0 <= N <= 15


# Output Format

# A list on a single line containing the cubes of the first N fibonacci numbers.

# Sample Input
# 5

# Sample Output
# [0, 1, 1, 8, 27]

n = int(raw_input().strip())

def fibs(n):
    fib_seq = [0, 1]
    i = 3
    
    while i <= n:
        fib_seq.append(fib_seq[-1] + fib_seq[-2])
        i += 1
    return fib_seq[:n]                              # beware that when n == 0 ([]) and n == 1 ([0]) we must use list indexing 
                                                    # in order to get the correct results

seq = fibs(n)
seq = map(lambda x: x ** 3, seq)
print seq