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Fix sub-byte bit placement in boolbv convert_byte_update #8960
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,7 @@ | ||
| int main() | ||
| { | ||
| unsigned x; | ||
| __CPROVER_bitvector[1] *p = (__CPROVER_bitvector[1] *)&x; | ||
| *p = 0; | ||
| __CPROVER_assert((x & 0x80u) == 0u, "MSB of byte 0 is cleared"); | ||
| } |
11 changes: 11 additions & 0 deletions
11
regression/cbmc/byte_update_sub_byte1/symbolic-offset.desc
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,11 @@ | ||
| CORE | ||
| symbolic.c | ||
| --little-endian --no-simplify | ||
| ^VERIFICATION SUCCESSFUL$ | ||
| ^EXIT=0$ | ||
| ^SIGNAL=0$ | ||
| -- | ||
| ^warning: ignoring | ||
| -- | ||
| Same as test.desc but with a symbolic (constrained-to-0) byte offset, | ||
| exercising the variable-offset branch of convert_byte_update. |
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,9 @@ | ||
| int main() | ||
| { | ||
| unsigned x; | ||
| unsigned offset; | ||
| __CPROVER_assume(offset == 0); | ||
| __CPROVER_bitvector[1] *p = (__CPROVER_bitvector[1] *)((char *)&x + offset); | ||
| *p = 0; | ||
| __CPROVER_assert((x & 0x80u) == 0u, "MSB of byte 0 is cleared"); | ||
| } |
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,13 @@ | ||
| CORE | ||
| main.c | ||
| --little-endian --no-simplify | ||
| ^VERIFICATION SUCCESSFUL$ | ||
| ^EXIT=0$ | ||
|
tautschnig marked this conversation as resolved.
|
||
| ^SIGNAL=0$ | ||
| -- | ||
| ^warning: ignoring | ||
| -- | ||
| Writing a 1-bit zero through a __CPROVER_bitvector[1] pointer must | ||
| clear the MSB of the first byte, not the LSB. The --no-simplify flag | ||
| is needed to exercise the boolbv convert_byte_update path directly. | ||
| This test uses a constant offset (byte 0). | ||
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We really need to find a better mechanism to test these things that does not involve turning off the simplifier.
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Yes, but this is just another example where the simplifier pretty much does what the back-end would otherwise do. In other words: I was not able to create a test that the simplifier wouldn't already rewrite to an expression that does not have the corner case that's being tackled here.